If you've been wanting to walk through New York City topless, now's your chance.
GoTopless Day is taking place in Manhattan on Sunday. It falls on Women's Equality Day, which recognizes Aug. 26, 1920, when women were given the right to vote in the United States.
Parades are scheduled across the country -- including Chicago, Washington, D.C., Phoenix, and Venice Beach, California -- and internationally.
It is legal to be topless in public in a majority of U.S. states, including New York, but organizers also hope to make going topless more acceptable.
Here are the details about the NYC event:
Sunday, Aug. 26, at noon
-Start on West 58th Street between Eighth and Ninth avenues
-Turn south onto Broadway and continue down to 48th Street
-Walk east on 48th Street to Sixth Avenue
-End at Bryant Park, where speeches will take place